Module 10 - Chartwork

Worked DR to EP: Coordinates and Assumptions

Start from the fictional fix 50°00.0′N 001°00.0′W. The yacht travels on 090°T through the water at 6 kn for two hours with no leeway, so its DR displacement is 12 M east. Near 50°N, one minute of longitude spans approximately cos 50° = 0.643 M. The longitude change is therefore 12 ÷ 0.643 = 18.7′ east.

Moving 18.7′ east from 001°00.0′W reduces the west longitude to 000°41.3′W. The 1400 DR is 50°00.0′N 000°41.3′W. Apply a steady stream setting 180°T at 2 kn for two hours: drift is 4 M south, equal to 4.0′ of latitude. The 1400 EP is 49°56.0′N 000°41.3′W.

The calculation assumes the start was accepted, 090°T and 6 kn were maintained, leeway was negligible, the stream remained representative and the short east-west conversion used an appropriate latitude. Mark and time DR and EP, retain an uncertainty area and compare with depth, visual, radar or checked GNSS evidence before using the result near danger.

  • 12 M east at 50°N changes longitude by about 18.7′
  • The DR is 50°00.0′N 000°41.3′W
  • 4 M south changes latitude by 4.0′
  • The EP is 49°56.0′N 000°41.3′W
  • Coordinate precision does not remove input uncertainty
PositionLatitudeLongitudeStatus
Start50°00.0′N001°00.0′WAccepted fix at 1200
DR50°00.0′N000°41.3′W12 M east through water
EP49°56.0′N000°41.3′WAdds 4 M south stream

Optional quick check

Section 8 of 13

Why is 12 M east at 50°N more than 12 minutes of longitude?

Choose one answer
Sources and factual review

Reviewed 20 August 2026 - Compass Revision editorial review.

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